Re: [Rd] Make as.factor an S3 generic?

From: William Dunlap <wdunlap_at_tibco.com>
Date: Wed, 20 Apr 2011 10:13:38 -0700

> -----Original Message-----
> From: r-devel-bounces_at_r-project.org
> [mailto:r-devel-bounces@r-project.org] On Behalf Of Martin Morgan
> Sent: Wednesday, April 20, 2011 9:56 AM
> To: R-devel_at_r-project.org
> Subject: [Rd] Make as.factor an S3 generic?
>
> as.factor / as.ordered is not written as a generic. This differs from
> as.numeric, as.matrix, and other as.*. The following seems to address
> this and does not break make check-all.

Why did you decide to make as.factor() generic instead of factor()?

Bill Dunlap
Spotfire, TIBCO Software

wdunlap tibco.com



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