Hi all,
Thanks for the replies, but I realize I've done a bad job explaining my problem. To help, I've created some sample data to explain the problem.
df <- data.frame(x=c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12), y=c(109, 232, 363, 496, 625, 744, 847, 928, 981, 1000, 979, 912), s=c(109, 341, 704, 1200, 1825, 2569, 3416, 4344, 5325, 6325, 7304, 8216))
In this data frame, y results from y = x * b1 + x^2 * b2 + x^3 * b3 and s is sum of the current y and all previous y (s3 = y1 + y2 + y3).
I know I can find b1, b2 and b3 using:
lm(y ~ 0 + x + I(x^2) + I(x^3), data=df)
yielding...
Coefficients:
x I(x^2) I(x^3)
100 10 -1
However, I need to find b1, b2 and b3 using the s column. The reason
being, I don't actually know the values of y in the actual data set. And
in the actual data, I only have a few of the values. Imagine this data is
being used a reward schedule for like a loyalty points program. y
represents the number of points needed for each level while s is the total
number of points to reach that level. In the real problem, my data looks
more like this:
d <- data.frame(x=c(1, 4, 9, 12), s=c(109, 1200, 5325, 8216))
Where I need to use a few sample points to help define the parameters of
the curve.
thanks again and hopefully this makes the problem a bit clearer.
robbie
On Fri, May 18, 2012 at 7:40 PM, David Winsemius <dwinsemius_at_comcast.net>wrote:
>
[[alternative HTML version deleted]]
> On May 18, 2012, at 1:44 PM, Robbie Edwards wrote:
>
> Hi all,
>>
>> I'm trying to model some data where the y is defined by
>>
>> y = summation[1 to 50] B1 * x + B2 * x^2 + B3 * x^3
>>
>> Hopefully that reads clearly for email.
>>
>>
> cumsum( rowSums( cbind(B1 * x, B2 * x^2, B3 * x^3)))
>
>
>
> Anyway, if it wasn't for the summation, I know I would do it like this
>>
>> lm(y ~ x + x2 + x3)
>>
>> Where x2 and x3 are x^2 and x^3.
>>
>> However, since each value of x is related to the previous values of x, I
>> don't know how to do this. Any help is greatly appreciated.
>>
>>
>>
>
> David Winsemius, MD
> West Hartford, CT
>
>
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