From: Shubha Vishwanath Karanth <shubhak_at_ambaresearch.com>

Date: Wed, 23 Jul 2008 19:33:30 +0530

R-help_at_r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 23 Jul 2008 - 15:27:27 GMT

Date: Wed, 23 Jul 2008 19:33:30 +0530

c(36,100,164,228,292,356,420,484,548,612)

aggregate(x,list(rep(1:10,each=8)),sum)[-1]

rowsum(x,group=rep(1:10,each=8))

But without grouping, can I achieve the required? Any other ways of doing this?

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 23 Jul 2008 - 15:27:27 GMT

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