From: Agustin Lobo (alobo@ija.csic.es)
Date: Mon 23 Jul 2001 - 07:45:04 EST
Message-id: <Pine.OSF.3.96.1010722234411.13791A-100000@ija.csic.es>
Given a list as such:
> milista
$"1":
[1] 23 25 11
$"2":
[1] 34 2
$"3":
[1] 12 1 0 1050 2
What's faster:
> a <- NULL
> for (i in names(milista)){
+ a <- c(a,(mean(milista[[i]])))
+ }
or
a <- lapply(milista,mean)
?
(I understand that the second option
is nicer and more compact, but is it
faster?).
Thanks
Agus
Dr. Agustin Lobo
Instituto de Ciencias de la Tierra (CSIC)
Lluis Sole Sabaris s/n
08028 Barcelona SPAIN
tel 34 93409 5410
fax 34 93411 0012
alobo@ija.csic.es
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