From: Peter Dalgaard BSA (p.dalgaard@biostat.ku.dk)
Date: Sat 12 Jan 2002 - 02:50:37 EST
Message-id: <x21ygwnaya.fsf@blueberry.kubism.ku.dk>
Jim Lindsey <james.lindsey@luc.ac.be> writes:
> > Only a valid interpretation with k integer (the rate need not be
> > one). But the rate of the resulting gamma process is still
> > dgamma/(1-pgamma). Jim
> >
> > >
> > >
> > > It would probably make better sense to have rate=1/k in that case, but
> > > then there's the compatibility issue. In general, it would make sense
> > > to have the rate defined as the events per time unit of a (stationary)
> > > renewal process with a given interarrival distribution, alias 1/mean.
>
> PS The rate per time unit of a stationary renewal process is only
> constant and equal to 1/mean for a Poisson process i.e. exponential
> interarrival times. Jim
Are you sure? The *marginal* rate, i.e. the probability of observing
an event in [t,t+dt) should be independent of t, by stationarity. The
*conditional* rate given no event before time t is of course only a
constant in the (memoryless) Poisson process.
-- O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - (p.dalgaard@biostat.ku.dk) FAX: (+45) 35327907 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request@stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
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