From: A.J. Rossini (rossini@blindglobe.net)
Date: Thu 10 Jan 2002 - 15:50:46 EST
Message-id: <87r8oyu7vd.fsf@jeeves.blindglobe.net>
>>>>> "AP" == Andrew Perrin <andrew_perrin@unc.edu> writes:
AP> I'd like to get summary statistics (really just a mean would
AP> be fine) for a vector in a data frame, but split based on the
AP> value of another vector. That is, I have a data frame
AP> (hcd.df) with variables datecat (which is always 1 or 2) and
AP> auth.sum (-8..+8). I've used xtabs to get chi-square
AP> comparisons, but what I need now is a simple mean of auth.sum
AP> where datecat is 1 and another where datecat is 2. Thanks for
AP> any advice.
Something like :
lapply(split(hcd.df$auth.sum,hcd.df$datecat),mean)
?
-- A.J. Rossini Rsrch. Asst. Prof. of Biostatistics U. of Washington Biostatistics rossini@u.washington.edu FHCRC/SCHARP/HIV Vaccine Trials Net rossini@scharp.org -------------- http://software.biostat.washington.edu/ -------------- FHCRC: M-W: 206-667-7025 (fax=4812)|Voicemail is pretty sketchy/use Email UW: T-Th: 206-543-1044 (fax=3286)|Change last 4 digits of phone to FAX Rosen: (Mullins' Lab) Fridays, and I'm unreachable except by email. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request@stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
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