From: RCulloch <ross.culloch_at_dur.ac.uk>

Date: Tue, 01 Jun 2010 06:32:22 -0700 (PDT)

Date: Tue, 01 Jun 2010 06:32:22 -0700 (PDT)

FROM TO DIST ID HR DD MM YY ANIMAL DAY 1 1 1 2.63981 'A1' 9 30 9 7 1 1 2 1 2 0.00000 'A1' 9 30 9 7 1 1 3 1 3 6.95836 'A1' 9 30 9 7 1 1 4 1 4 8.63809 'A1' 9 30 9 7 1 1 5 1 1 0.00000 'A1.1' 9 30 9 7 7 1 6 1 2 2.63981 'A1.1' 9 30 9 7 7 1 7 1 3 8.03071 'A1.1' 9 30 9 7 7 1 8 1 4 8.90896 'A1.1' 9 30 9 7 7 1 9 1 1 8.90896 'A2' 9 30 9 7 1 1 10 1 2 8.63809 'A2' 9 30 9 7 1 1 11 1 3 2.85602 'A2' 9 30 9 7 1 1 12 1 4 0.00000 'A2' 9 30 9 7 1 1 13 1 1 8.03071 'A2.1' 9 30 9 7 7 1 14 1 2 6.95836 'A2.1' 9 30 9 7 7 1 15 1 3 0.00000 'A2.1' 9 30 9 7 7 1 16 1 4 2.85602 A2.1' 9 30 9 7 7 1 17 1 1 3.53695 'A1' 10 30 9 7 1 1 18 1 2 4.32457 'A1' 10 30 9 7 1 1 19 1 3 0.00000 'A1' 10 30 9 7 1 1 20 1 4 8.85851 'A1' 10 30 9 7 1 1 21 1 5 12.09194 'A1' 10 30 9 7 1 1 22 1 1 7.44743 'A1.1' 10 30 9 7 7 1 23 1 2 0.00000 'A1.1' 10 30 9 7 7 1 24 1 3 4.32457 'A1.1' 10 30 9 7 7 1 25 1 4 13.16728 'A1.1' 10 30 9 7 7 1 26 1 5 16.34761 'A1.1' 10 30 9 7 7 1 27 1 1 6.13176 'A2' 10 30 9 7 1 1 28 1 2 13.16728 'A2' 10 30 9 7 1 1 29 1 3 8.85851 'A2' 10 30 9 7 1 1 30 1 4 0.00000 'A2' 10 30 9 7 1 1 31 1 5 3.40726 'A2' 10 30 9 7 1 1 32 1 1 9.03345 'A2.1' 10 30 9 7 7 1 33 1 2 16.34761 'A2.1' 10 30 9 7 7 1 34 1 3 12.09194 'A2.1' 10 30 9 7 7 1 35 1 4 3.40726 'A2.1' 10 30 9 7 7 1 36 1 5 0.00000 'A2.1' 10 30 9 7 7 1 37 1 1 0.00000 'MALE1' 10 30 9 7 12 1 38 1 2 7.44743 'MALE1' 10 30 9 7 12 1 39 1 3 3.53695 'MALE1' 10 30 9 7 12 1 40 1 4 6.13176 'MALE1' 10 30 9 7 12 1 41 1 5 9.03345 'MALE1' 10 30 9 7 12 1

So the loop is:

DIST_LOOP<-matrix(NA,NA,ncol=11)

for (i in 1:33){

SEL_DAY<-seal_dist[seal_dist[,10]==i,] SEL_DAY[i]=dist[i] print(paste("DAY", i, "of 33")) for (s in 1:11){ SEL_HR<-SEL_DAY[SEL_DAY[,5]==s,] print(paste("HR", s, "of 11")) indx <- subset(SEL_HR, SEL_HR$DIST == 0) SEL_HR$TO_ID <- indx$ID[match(SEL_HR$TO, indx$TO)] DIST_LOOP[i,]<-SEL_HR

}}

But storing the data in the DIST_LOOP matrix doesn't work, I am just told in another post that a list might be better than a matrix?

I hope this makes more sense!?

Many thanks,

Ross

-- View this message in context: http://r.789695.n4.nabble.com/storing-output-data-from-a-loop-that-has-varying-row-numbers-tp2238396p2238483.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help_at_r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.Received on Tue 01 Jun 2010 - 13:45:38 GMT

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