# [R] The curious special case of "~ (a + b)/c"

From: Nathaniel Smith <njs_at_pobox.com>
Date: Sat, 05 Jun 2010 13:30:54 -0700

This isn't at all an urgent practical question, but recently while exploring the details of how R formulas are interpreted, I learned of this funny special case for how / interacts with +. In all of the following cases, the multiplication-like operator simply distributes over addition:
(a + b):c = a:c + a:c

```  a:(b + c) = a:b + a:c

(a + b)*c = a*c + b*c

a*(b + c) = a*b + a*c
a/(b + c) = a/b + a/c

```

But:
(a + b)/c = a + b + a:b:c, not a/c + b/c = a + a:c + b + b:c

Chambers and Hastie mention this, but give no explanation (page 29/30, "Slightly more subtle is...").

So for my own edification, does anyone know/care to speculate about why (a + b)/c works this way?

• Nathaniel

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