Re: [R] Duplicate dates in zoo objects

From: Joris Meys <jorismeys_at_gmail.com>
Date: Tue, 22 Jun 2010 17:54:16 +0200

Try this :
> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 7, 14) - 1

> x <- zoo(1:5, x.Date)

> x

2003-02-01 2003-02-03 2003-02-07 2003-02-07 2003-02-14

         1 2 3 4 5

> i <- match(unique(index(x)),rev(index(x)))

> x[i]

2003-02-01 2003-02-03 2003-02-07 2003-02-14

         1 2 4 5

Cheers
Joris

On Tue, Jun 22, 2010 at 4:35 PM, Research <risk2009_at_ath.forthnet.gr> wrote:
> Hello,
>
> I have a zoo time series read from an excel file which has some dates the
> same, such as the following example:
>
> 02/10/1995     4925.5
> 30/10/1995     4915.9
> 23/01/1996     4963.5
> 23/01/1996     5009.2
> 04/03/1996     5031.9     # here
> 04/03/1996     5006.5     # here
> 03/04/1996     5069.2
> 03/05/1996     5103.7
> 31/05/1996     5107.1
> 01/07/1996     5153.1
> 02/08/1996     5151.7
>
> Is there a simple way to keep the last  price of the ones that have the same
> dates?
>
> 04/03/1996    5031.9
> 04/03/1996    5006.5
>
> i.e., keep only the "04/03/1996    5006.5"  price and discard the previous
> one... Is there an implicit function that does that or do I need some sort
> of recursive algorithm?
>
> You can try a solution on this example (for convenience):
>
> x.Date <- as.Date("2003-02-01") + c(1, 3, 7, 7, 14) - 1
> x <- zoo(rnorm(5), x.Date)
>
> Zoo object  has 2 prices with same dates.
>
> Many thanks in advance,
> Costas
>
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>

-- 
Joris Meys
Statistical consultant

Ghent University
Faculty of Bioscience Engineering
Department of Applied mathematics, biometrics and process control

tel : +32 9 264 59 87
Joris.Meys_at_Ugent.be
-------------------------------
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Received on Tue 22 Jun 2010 - 16:42:42 GMT

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