Re: [Rd] Make as.factor an S3 generic?

From: William Dunlap <>
Date: Wed, 20 Apr 2011 10:13:38 -0700

> -----Original Message-----
> From:
> [] On Behalf Of Martin Morgan
> Sent: Wednesday, April 20, 2011 9:56 AM
> To:
> Subject: [Rd] Make as.factor an S3 generic?
> as.factor / as.ordered is not written as a generic. This differs from
> as.numeric, as.matrix, and other as.*. The following seems to address
> this and does not break make check-all.

Why did you decide to make as.factor() generic instead of factor()?

Bill Dunlap
Spotfire, TIBCO Software

wdunlap mailing list Received on Wed 20 Apr 2011 - 17:17:00 GMT

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