Re: [R] factor with numeric names

From: agent dunham <crosspide_at_hotmail.com>
Date: Fri, 25 Mar 2011 05:30:12 -0700 (PDT)

Dear all,

According to the post I was trying:

factorA = c(2,2,3,3,4,4,3,4,2,2)
levels(factorA <- c("lv1","lv2","lv3") )

But this returns NULL and doesn't change factor names.

Actually, my factor is included in a data.frame, so I also tried:

levels(df$factorA)[levels(df$factorA)=="2"] <- "lv1"  Also
levels(df$factorA)[levels(df$factorA)==2] <- "lv1" 
levels(df$factorA)[levels(df$factorA)=="3"] <- "lv2" 
levels(df$factorA)[levels(df$factorA)=="4"] <- "lv3" 

then I type table(df$factorA) and it doesn't work either.

After attach(df), I tried also this

for(i in 1:10)

   { if(factor(factorA)[i]==2) factorA[i]="lv2" else {;

      if(factor(factorA)[i]==3) factorA[i]="lv3" else {; 
      factorA[i]= "lv4"}}}}


Any help would be appreciated. Thanks, user_at_host.com

--
View this message in context: http://r.789695.n4.nabble.com/factor-with-numeric-names-tp882535p3405247.html
Sent from the R help mailing list archive at Nabble.com.

______________________________________________
R-help_at_r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Received on Fri 25 Mar 2011 - 13:13:43 GMT

Archive maintained by Robert King, hosted by the discipline of statistics at the University of Newcastle, Australia.
Archive generated by hypermail 2.2.0, at Fri 25 Mar 2011 - 14:40:24 GMT.

Mailing list information is available at https://stat.ethz.ch/mailman/listinfo/r-help. Please read the posting guide before posting to the list.

list of date sections of archive