Re: [R] Avoiding loop

From: Dennis Murphy <djmuser_at_gmail.com>
Date: Mon, 18 Apr 2011 10:13:48 -0700

Hi:

Try the expm package. Using your example,

> R = A%*%B
> for(i in 1:100)

```+ {
+        R = R%*%B
+ }

> R
[,1]         [,2]         [,3]         [,4]         [,5]
[1,] 9.934879e+47 1.098761e+48 8.868476e+47 7.071831e+47 6.071370e+47
[2,] 1.492692e+48 1.650862e+48 1.332468e+48 1.062526e+48 9.122090e+47
[3,] 6.693145e+47 7.402373e+47 5.974708e+47 4.764305e+47 4.090293e+47
```
[4,] 5.895689e+47 6.520416e+47 5.262850e+47 4.196661e+47 3.602954e+47 [5,] 8.347321e+47 9.231830e+47 7.451326e+47 5.941778e+47 5.101187e+47

library(expm)
# The matrix power function is an operator % ^ %
> A %*% (B %^% 101)

[,1] [,2] [,3] [,4] [,5]

```[1,] 9.934879e+47 1.098761e+48 8.868476e+47 7.071831e+47 6.071370e+47
[2,] 1.492692e+48 1.650862e+48 1.332468e+48 1.062526e+48 9.122090e+47
[3,] 6.693145e+47 7.402373e+47 5.974708e+47 4.764305e+47 4.090293e+47
[4,] 5.895689e+47 6.520416e+47 5.262850e+47 4.196661e+47 3.602954e+47
[5,] 8.347321e+47 9.231830e+47 7.451326e+47 5.941778e+47 5.101187e+47

```

user system elapsed
0.02 0.00 0.01
> system.time(replicate(1000, {R = A%*%B

```+     for(i in 1:100)
+ {
+        R = R%*%B
+ }  }))
```

user system elapsed
0.15 0.00 0.15

HTH,
Dennis

On Mon, Apr 18, 2011 at 9:06 AM, Filoche <pmassicotte_at_hotmail.com> wrote:
> Hi everyone.

```>
```

> I'm using matrix product such as :
```>
>
```

> #Generate some data
> NCols = 5
> NRows = 5
> A = matrix(runif(NCols*NRows), ncol=NCols)
> B = matrix(runif(NCols*NRows), ncol=NCols)
```>
```

> #First calculation
> R = A%*%B
```>
>
```

> for(i in 1:100)
> {
>        R = R%*%B
> }
```>
>
```

> I would like to know if it was possible to avoid the loop by using something
> like mapply or anything else.
```>
```

> Phil
```>
```

> --
> View this message in context: http://r.789695.n4.nabble.com/Avoiding-loop-tp3457963p3457963.html
> Sent from the R help mailing list archive at Nabble.com.
```>

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