Re: [R] calculations with vectors of unequal length

From: Scott Chamberlain <scttchamberlain4_at_gmail.com>
Date: Wed, 27 Apr 2011 06:54:33 -0500

> df.1 <- merge(df.1, df.2, by = "year") > df.1$sum <- df.1$number.x + df.1$number.y
> df.1 year level number.x number.y sum 1 1 a 11 21 32 2 1 a 17 21 38 3 1 a 14 21 35 4 2 b 12 22 34 5 2 b 15 22 37 6 2 b 18 22 40 7 3 c 16 23 39 8 3 c 13 23 36 9 3 c 19 23 42

Scott

On Wednesday, April 27, 2011 at 6:30 AM, E Hofstadler wrote:
> Hi there,
>
> this is probably simple but I can't seem to figure it out by myself...
>
> I have two dataframes (df.1 and df.2):
>
> df.1 <- data.frame(year=factor(rep(1:3,3)), level=rep(letters[1:3],3),
> number=c(11:19))
> df.2 <- data.frame(year=factor(c(1:5)), number=c(21:25))
>
> I would like to create a new variable df.1$new, which is supposed to
> be the sum of each element of df.1$number and those elements of
> df.2$number, where df.2$year equals df.1$year.
>
> What would be the most efficient way of doing this?
>
> Regards,
> EH
>
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