# Re: [R] calculations with vectors of unequal length

From: Jeremy Hetzel <jthetzel_at_gmail.com>
Date: Wed, 27 Apr 2011 04:45:04 -0700 (PDT)

See ?merge.

df.1 <- data.frame(year=factor(rep(1:3,3)), level=rep(letters[1:3],3), number=c(11:19))
df.2 <- data.frame(year=factor(c(1:5)), number=c(21:25))

df.3 <- merge(df.1, df.2, by = "year")
df.3\$new <- with(df.3, number.x + number.y)

Jeremy

On Wednesday, April 27, 2011 7:30:13 AM UTC-4, E Hofstadler wrote:
>
> Hi there,
>
> this is probably simple but I can't seem to figure it out by myself...
>
> I have two dataframes (df.1 and df.2):
>
> df.1 <- data.frame(year=factor(rep(1:3,3)), level=rep(letters[1:3],3),
> number=c(11:19))
> df.2 <- data.frame(year=factor(c(1:5)), number=c(21:25))
>
> I would like to create a new variable df.1\$new, which is supposed to
> be the sum of each element of df.1\$number and those elements of
> df.2\$number, where df.2\$year equals df.1\$year.
>
> What would be the most efficient way of doing this?
>
> Regards,
> EH
>
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>

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 27 Apr 2011 - 12:54:39 GMT

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