Re: [R] Putting a loop in a function

From: Berend Hasselman <>
Date: Sat, 02 Apr 2011 02:51:49 -0500 (CDT)

Ben Hunter wrote:
> I'm stuck here. The following code works great if I just use it on the
> command line in a 'for' loop. Once I try to define it as a function as
> seen
> below, I get bad results. I'm trying to return a vector of column indices
> based on a short string that is contained in a selection (length of about
> 70) of long column names that changes from time to time. Is there an
> existing function that will do this for me? The more I think about this
> problem, the more I feel there has to be a function out there. I've not
> found it.
> ind &lt;- function(col, string, vector){ # this is really the problem. I
> don't
> feel like I'm declaring these arguments properly.
> indices &lt;- vector(mode = 'numeric') # I am not entirely confident
> that
> this use is necessary. Is indices &lt;- c() okay?
> for (i in 1:length(col)){
> num &lt;- regexpr(str, col[i])
> if (num != -1){
> indices &lt;- c(vector, i) # I've also had success with indices
> &lt;-
> append(indices, i)
> }
> }
> indices
> }
> ind(d[,'Column.I.want'], 'string', 'output.vector')
> Am I wrong here? I've read that the last statement in the function is what
> it will return, and what I want is a vector of integers.

It is not clear what you want. Give a simple example with input and desired output.
About your function:


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Received on Sat 02 Apr 2011 - 07:57:18 GMT

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