# Re: [R] Calculated mean value based on another column bin from dataframe.

From: Fabrice Tourre <fabrice.ciup_at_gmail.com>
Date: Wed, 06 Apr 2011 15:46:43 +0200

Thank you very much for your suggestion.

It is obvious that your method is better than me.

Is it possible to use cut, table,by etc? Whether there is some aggregate function in R can do this?

Thanks.

On Wed, Apr 6, 2011 at 2:16 PM, Henrique Dallazuanna <wwwhsd_at_gmail.com> wrote:
> Try this:
>
> fil <- sapply(ran, '<', e1 = dat[,1]) & sapply(ran[2:(length(ran) +
> 1)], '>=', e1 = dat[,1])
> mm <- apply(fil, 2, function(idx)mean(dat[idx, 2]))
>
> On Wed, Apr 6, 2011 at 5:48 AM, Fabrice Tourre <fabrice.ciup_at_gmail.com> wrote:
>> Dear list,
>>
>> I have a dataframe with two column as fellow.
>>
>>       V1      V2
>>  0.15624 0.94567
>>  0.26039 0.66442
>>  0.16629 0.97822
>>  0.23474 0.72079
>>  0.11037 0.83760
>>  0.14969 0.91312
>>
>> I want to get the column V2 mean value based on the bin of column of
>> V1. I write the code as fellow. It works, but I think this is not the
>> elegant way. Any suggestions?

>>
>> ran<-seq(0,0.5,0.05)
>> mm<-NULL
>> for (i in c(1:(length(ran)-1)))
>> {
>>    fil<- dat[,1] > ran[i] & dat[,1]<=ran[i+1]
>>    m<-mean(dat[fil,2])
>>    mm<-c(mm,m)
>> }
>> mm
>>
>> Here is the first 20 lines of my data.
>>
>> structure(list(V1 = c(0.15624, 0.26039, 0.16629, 0.23474, 0.11037,
>> 0.14969, 0.16166, 0.09785, 0.36417, 0.08005, 0.29597, 0.14856,
>> 0.17307, 0.36718, 0.11621, 0.23281, 0.10415, 0.1025, 0.04238,
>> 0.13525), V2 = c(0.94567, 0.66442, 0.97822, 0.72079, 0.8376,
>> 0.91312, 0.88463, 0.82432, 0.55582, 0.9429, 0.78956, 0.93424,
>> 0.87692, 0.83996, 0.74552, 0.9779, 0.9958, 0.9783, 0.92523, 0.99022
>> )), .Names = c("V1", "V2"), row.names = c(NA, 20L), class = "data.frame")
>>
>> ______________________________________________
>> R-help_at_r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Henrique Dallazuanna
> Curitiba-Paraná-Brasil
> 25° 25' 40" S 49° 16' 22" O
>
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