Re: [R] Need a more efficient way to implement this type of logic in R

From: Phil Spector <spector_at_stat.berkeley.edu>
Date: Wed, 06 Apr 2011 13:58:14 -0700 (PDT)

Walter -

    Since your codes represent numbers, you could use something like this:

chk = as.numeric((hh.sub$HHFAMINC)
hh.sub$CS_FAMINC = cut(chk,c(-10,0,5,10,15,17,18),labels=c(0,1:5))

On Wed, 6 Apr 2011, Walter Anderson wrote:

> I have cobbled together the following logic. It works but is very slow.
> I'm sure that there must be a better r-specific way to implement this kind of
> thing, but have been unable to find/understand one. Any help would be
> appreciated.
>
> hh.sub <- households[c("HOUSEID","HHFAMINC")]
> for (indx in 1:length(hh.sub$HOUSEID)) {
> if ((hh.sub$HHFAMINC[indx] == '01') | (hh.sub$HHFAMINC[indx] == '02') |
> (hh.sub$HHFAMINC[indx] == '03') | (hh.sub$HHFAMINC[indx] == '04') |
> (hh.sub$HHFAMINC[indx] == '05'))
> hh.sub$CS_FAMINC[indx] <- 1 # Less than $25,000
> if ((hh.sub$HHFAMINC[indx] == '06') | (hh.sub$HHFAMINC[indx] == '07') |
> (hh.sub$HHFAMINC[indx] == '08') | (hh.sub$HHFAMINC[indx] == '09') |
> (hh.sub$HHFAMINC[indx] == '10'))
> hh.sub$CS_FAMINC[indx] <- 2 # $25,000 to $50,000
> if ((hh.sub$HHFAMINC[indx] == '11') | (hh.sub$HHFAMINC[indx] == '12') |
> (hh.sub$HHFAMINC[indx] == '13') | (hh.sub$HHFAMINC[indx] == '14') |
> (hh.sub$HHFAMINC[indx] == '15'))
> hh.sub$CS_FAMINC[indx] <- 3 # $50,000 to $75,000
> if ((hh.sub$HHFAMINC[indx] == '16') | (hh.sub$HHFAMINC[indx] == '17'))
> hh.sub$CS_FAMINC[indx] <- 4 # $75,000 to $100,000
> if ((hh.sub$HHFAMINC[indx] == '18'))
> hh.sub$CS_FAMINC[indx] <- 5 # More than $100,000
> if ((hh.sub$HHFAMINC[indx] == '-7') | (hh.sub$HHFAMINC[indx] == '-8') |
> (hh.sub$HHFAMINC[indx] == '-9'))
> hh.sub$CS_FAMINC[indx] = 0
> }
>
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>



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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 06 Apr 2011 - 21:02:07 GMT

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