Re: [Rd] Fastest non-overlapping binning mean function out there?

From: Terry Therneau <therneau_at_mayo.edu>
Date: Wed, 03 Oct 2012 07:50:45 -0500

Look at rowsum. It's pretty fast C code.

Terry T

On 10/03/2012 05:00 AM, r-devel-request_at_r-project.org wrote:
> Hi,
>
> I'm looking for a super-duper fast mean/sum binning implementation
> available in R, and before implementing z = binnedMeans(x y) in native
> code myself, does any one know of an existing function/package for
> this? I'm sure it already exists. So, given data (x,y) and B bins
> bx[1]< bx[2]< ...< bx[B]< bx[B+1], I'd like to calculate the
> binned means (or sums) 'z' such that z[1] = mean(x[bx[1]<= x& x<
> bx[2]]), z[2] = mean(x[bx[2]<= x& x< bx[3]]), .... z[B]. Let's
> assume there are no missing values and 'x' and 'bx' is already
> ordered. The length of 'x' is in the order of 10,000-millions. The
> number of elements in each bin vary.
>
> Thanks,
>
> Henrik



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