From: Antonin Ferry <antoninferry_at_voila.fr>

Date: Wed 13 Sep 2006 - 09:00:15 GMT

# Take a data set of counts for two traitments, one containing only zeros

response=c(A,B)

mydata=data.frame(traitment ,response)

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed Sep 13 19:03:22 2006

Date: Wed 13 Sep 2006 - 09:00:15 GMT

Dear members,

here is my trouble: My data consists of counts of trapped insects in different attractive traps. I usually use GLMs with a poisson error distribution to find out the differences between my traitments (and to look at other factor effects). But for some dataset where one traitment contains only zeros, GLM with poisson family fail to find any difference between this particular traitment and anyother one (even with traitment that have trapped a lot of insects). GLMs with gaussian family does not seem to have the same problem but GLMs with binomial family does.
I'm not sure if it is a statistical problem or if it comes from R... in the latter case I think some solution exists (perhaps in the options of the glm() function ?).
Thank you for your help.

Here I figure out an exemple to past in the console:

## START ##############################################################################

# Take a data set of counts for two traitments, one containing only zeros

A=c(0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0) B=c(1,0,0,0,2,1,0,0,1,2,0,0,0,1,2,2,0,1,1,0,1,0,2,1,1,0,1,2,0,1,0,1,1,1,0,1,1,1,0,1) traitment=c(rep("A",40),rep("B",40))

response=c(A,B)

mydata=data.frame(traitment ,response)

# Make a GLM on this dataset , with "family=poisson"

g=glm(response~traitment, data=mydata, family=poisson)
anova.glm(g,test="Chisq")

# There is an effect of the traitment ...

summary(g)

# But traitment A does not differ from traitment B ! ! ! (the pvalue is always close from 1 in such cases)

# Now if you replace only one zero of the A reponse to 1, the GLM works properly:

mydata[1,2]=1

g=glm(response~traitment, data=mydata, family=poisson)
anova.glm(g,test="Chisq")

summary(g)

##################################################################################### END ##

Antonin Ferry (PhD)

"Laboratoire d'Ecobiologie des Insectes Parasitoides"
http://www.parasitoides.univ-rennes1.fr

UniversitĂ© de Renes1, FRANCE

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed Sep 13 19:03:22 2006

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