# Re: [R] Fill a matrix with vectors of different lengths

Date: Mon 16 Oct 2006 - 08:54:12 GMT

for (i in 1:length(v)) {

```      bi <- binc(v[1:i])
mat[1:length(bi),i]=mat[1:length(bi),i]+bi
```
}

On 16/10/06, Serguei Kaniovski <kaniovsk@wifo.ac.at> wrote:
> Hello,
>
> how can I best fill a (fixed) matrix with vectors of varying lengths by
> column, setting the superfluous elements to zero? Here is my code:
>
> v<-(1,1,2,3,4,6)
>
> binc<-function(x){
> l<-sum(x)+1
> y<-c(1,rep(0,l-1))
> for (i in x) y<-y+c(rep(0,i),y)[1:l]
> }
>
> mat<-matrix(0, nrow=sum(v)+1, ncol=length(v))
> for (i in 1:length(v)) mat[,i]=mat[,i]+binc(v[1:i])
>
> the expression in the for-loop produces an error since mat[,i] and
> binc(v[1:i]) are of unequal lengths, except on the last iteration.
>
> Serguei
> --
> ___________________________________________________________________
>
> Austrian Institute of Economic Research (WIFO)
>
> Name: Serguei Kaniovski P.O.Box 91
> Tel.: +43-1-7982601-231 Arsenal Objekt 20
> Fax: +43-1-7989386 1103 Vienna, Austria
> Mail: Serguei.Kaniovski@wifo.ac.at
>
> http://www.wifo.ac.at/Serguei.Kaniovski
>
> ______________________________________________
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> and provide commented, minimal, self-contained, reproducible code.
>

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University of Oxford
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