From: Gabor Grothendieck <ggrothendieck_at_gmail.com>

Date: Sat 28 Oct 2006 - 20:37:20 GMT

> But how to aggregate, for example, 4 consecutive days with that range of

*> values? I've played with aggregate(z,index(z), ...) but I can't find the
*

*> right FUN to do this
*

> Thanks in advance,

> Antonio

>

>

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sun Oct 29 07:41:49 2006

Date: Sat 28 Oct 2006 - 20:37:20 GMT

# test data

x <- c(1:4, 6:8, 10:14)

z <- zoo(x, as.Date(x))

# idx is 1 for first run, 2 for second run, etc. idx <- cumsum(c(1, diff(z) != 1))

# average over each run using the time of the end of run for the result # replace ends with starts if that is preferred aggregate(z, ends, mean)

On 10/28/06, antonio rodriguez <antonio.raju@gmail.com> wrote:

> Gabor Grothendieck escribió:

*> > On 10/28/06, antonio rodriguez <antonio.raju@gmail.com> wrote:
**> >> Hi,
**> >>
**> >> Having an zoo object I can subset it to obtain the days where I have the
**> >> values within some range:
**> >>
**> >> is.zoo(z)
**> >> TRUE
**> >>
**> >> subset(z[,1], z[,1]>=5 & z[,1]<= 10) #Yields: Year(day)
**> >>
**> >> 1988(13) 1988(14) 1988(16) 1988(20) 1988(21) 1988(22) 1988(25)
**> >> 1988(26)
**> >> 7.973946 9.933518 7.978227 7.512960 6.641862 5.667780 5.721358
**> >> 6.863729
**> >> 1988(27) 1988(28) 1988(29) 1988(30) 1988(32) 1988(33) 1988(34)
**> >> 1988(35)
**> >> 9.600000 9.049846 9.213438 6.412746 5.543606 7.881596 6.373102
**> >> 7.220562
**> >> ..................................................................................................................
**> >>
**> >> ..................................................................................................................
**> >>
**> >>
**> >> How do I could refine the search in order to obtain those consecutive
**> >> days within a specific range? In the above extract:
**> >>
**> >> 1988(26) 1988(27) 1988(28) 1988(29) 1988(30) 1988(33) 1988(34)
**> >> 1988(35)
**> >> 6.863729 9.600000 9.049846 9.213438 6.412746 7.881596 6.373102
**> >> 7.220562
**> >>
**> >
**> > If zz is a zoo series time(zz) or equivalently index(zz) gives the times.
*

>

> But how to aggregate, for example, 4 consecutive days with that range of

>

> Thanks in advance,

>

> Antonio

>

>

R-help@stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sun Oct 29 07:41:49 2006

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