Re: [R] simple q: returning a logical vector of substring matches

From: Gabor Grothendieck <ggrothendieck_at_gmail.com>
Date: Sat 20 Jan 2007 - 19:32:18 GMT

Using the builtin month.abb try this:

  regexpr("ov", month.abb) > 0

Although not needed here, if "ov" were a character string that could have special characters such as . and * that have special meaning in a regular expression then do this to prevent such interpretation:

  regexpr("ov", month.abb, fixed = TRUE) > 0

See ?regexpr

On 1/20/07, lindeman@bard.edu <lindeman@bard.edu> wrote:
> I'm a relative R novice, and sometimes the simple things trip me up.
>
> Suppose I have
>
> a <- c("apple", "pear")
>
> and I want a logical vector of whether each of these strings contains
> "ear" (in this case, F T). What is the idiom?
>
> Quizzically,
> Mark Lindeman
>
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>



R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sun Jan 21 06:36:15 2007

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