From: jim holtman <jholtman_at_gmail.com>

Date: Wed 04 Apr 2007 - 11:51:31 GMT

# use list for the data

ans <- lapply(seq_along(m), function(x) rnorm(n, m[x], v[x])) # convert to integer

ansInt <- lapply(ans, as.integer)

# sort

ansSort <- lapply(ansInt, sort)

# show the results

ansSort

Date: Wed 04 Apr 2007 - 11:51:31 GMT

One of the things about R that you have to learn is vector operations. You try to avoid loops and also 'generating' variables -- this is where a list comes in very handy. To relate to Java, it is similar to 'struct'. Here is a program that does what you want to do; it uses lists and vectorized operations.

# generate some test data

m <- seq(5, 30, length=10) # means v <- m / 4 # variance n <- 50 # samples

# use list for the data

ans <- lapply(seq_along(m), function(x) rnorm(n, m[x], v[x])) # convert to integer

ansInt <- lapply(ans, as.integer)

# sort

ansSort <- lapply(ansInt, sort)

# show the results

ansSort

On 4/3/07, projection83 <mkurowski@gmail.com> wrote:

*>
**>
*

> I am used to java (well, i dont remember it really well, but anyway)

*>
**> I have having a really difficult time making simple loops to work. I got
**> the
**> following to work:
**>
**> ##
**> ##Creates objects Ux1, Ux2, Ux2 etc. that all contain n numbers in
**> a
**> random distribution
**> ##
**> m<-c(m1,m2,m3,m4,m5,m6,m7,m8,m9,m10)#these are defined as numbers
**> (means)
**> v<-c(v1,v2,v3,v4,v5,v6,v7,v8,v9,v10)#these are defined as numbers
**> (variances)
**> n<-50
**> for(k in 1:g)
**> {
**> assign( paste("Ux", k, sep=""), rnorm( n ,
**> assign(paste("m",1,sep=""),m[k]) , assign(paste("m",1,sep=""),v[k]) )
**> )
**> }
**>
**>
**> The above seems like a lot of work for such a simple feat, no?
**>
**> Also, I CANNot get the following to work in a loop manor:
**>
**> Ux1i<-as.integer(Ux1)
**> Ux2i<-as.integer(Ux2)
**> Ux3i<-as.integer(Ux3)
**>
**> or
**>
**> Sx1<-sort(Ux1i)
**> Sx2<-sort(Ux2i)
**> Sx3<-sort(Ux3i)
**>
**> Maybe I am just not using matrixes enough? but even that seems quite a lot
**> more complex than calling x<-matrix() then grabbing values by
**> x[j][k]...(java style if i remember correctly). the matrix help in R dosnt
**> make much sense to me. And also i am not sure why numeric() dosnt make you
**> define length before you use it, yet matrix() does. Is there some other
**> funciton that i should be using to make length not an issue?
**>
**>
**> All in all, I dont know if i am going about this loop stuff a reaaaaly
**> round
**> about way - Any help would make me much less loopy:Pthanks
**>
**>
**>
**> --
**> View this message in context:
**> http://www.nabble.com/Newbie%3A-Simple-loops%3A-complex-troubles-tf3523751.html#a9830574
**> Sent from the R help mailing list archive at Nabble.com.
**>
**> ______________________________________________
**> R-help@stat.math.ethz.ch mailing list
**> https://stat.ethz.ch/mailman/listinfo/r-help
**> PLEASE do read the posting guide
**> http://www.R-project.org/posting-guide.html
**> and provide commented, minimal, self-contained, reproducible code.
**>
*

-- Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem you are trying to solve? [[alternative HTML version deleted]] ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.Received on Wed Apr 04 21:55:07 2007

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