[R] creating a data frame from a list

From: Dimitri Szerman <dimitrijoe_at_gmail.com>
Date: Thu 05 Apr 2007 - 18:57:33 GMT

Dear all,

A few months ago, I asked for your help on the following problem:

I have a list with three (named) numeric vectors:

> lst = list(a=c(A=1,B=8) , b=c(A=2,B=3,C=0), c=c(B=2,D=0) )
> lst

\$a
A B
1 8

\$b
A B C
2 3 0

\$c
B D
2 0

Now, I'd love to use this list to create the following data frame:

> dtf = data.frame(a=c(A=1,B=8,C=NA,D=NA),

```+                  b=c(A=2,B=3,C=0,D=NA),
+                  c=c(A=NA,B=2,C=NA,D=0) )

> dtf
a    b     c
A   1   2  NA
B   8   3     2
```

C NA 0 NA
D NA NA 0

That is, I wish to "merge" the three vectors in the list into a data frame by their "(row)"names.

And I got the following answer:

library(zoo)
z <- do.call(merge, lapply(lst, function(x) zoo(x, names(x)))) rownames(z) <- time(z)
coredata(z)

However, it does not seem to be working. Here's what I get when I try it:

> lst = list(a=c(A=1,B=8) , b=c(A=2,B=3,C=0), c=c(B=2,D=0) )
> library(zoo)
> z <- do.call(merge, lapply(lst, function(x) zoo(x, names(x))))
Error in if (freq > 1 && identical(all.equal(freq, round(freq)), TRUE)) freq <- round(freq) :

missing value where TRUE/FALSE needed In addition: Warning message:
NAs introduced by coercion

and z was not created.

Any ideas on what is going on here?
Thank you,
Dimitri

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