Re: [R] test for nested factors

From: Christophe Pallier <christophe_at_pallier.org>
Date: Mon, 04 Jun 2007 17:51:45 +0200

Here are two functions I wrote, 'is.nested' and 'are.crossed', that check whether a factor is nested inside antoher one, or if both are crossed:

is.nested <- function (factor1,factor2)
  {
    # only one positive number per line in the f1 * f2 crosstable     all(apply(table(factor1,factor2)>0,1,sum) == 1)   }

are.crossed <- function (factor1,factor2)   { all(table(factor1,factor2) > 0 ) }

Christophe Pallier
www.pallier.org

On 6/4/07, Tim Bergsma <timb_at_metrumrg.com> wrote:
>
> Is there a conventional way to test for nested factors? I.e., if 'a'
> and 'b' are lists of same-length factors, does each level specified by
> 'a' correspond to exactly one level specified by 'b'?
>
> The function below seems to suffice, but I'd be happy to know of a more
> succinct solution, if it already exists.
>
> Thanks,
>
> Tim.
>
> ---
>
> "%nested.in%" <- function(x,f,...){
> #coerce to list
> if(!is.list(x))x<-list(x)
> if(!is.list(f))f<-list(f)
> #collapse to vector
> x <- tapply(x[[1]],x)
> f <- tapply(f[[1]],f)
> #analyse
> return(all(sapply(lapply(split(f,x),unique),length)==1))
> }
>
> CO2$Plant %nested.in% CO2[,c("Type","Treatment")] #TRUE
> CO2$Plant %nested.in% (CO2$uptake < mean(CO2$uptake)) #FALSE
>
> ______________________________________________
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> PLEASE do read the posting guide
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> and provide commented, minimal, self-contained, reproducible code.
>

-- 
Christophe Pallier (http://www.pallier.org)

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Received on Mon 04 Jun 2007 - 15:56:53 GMT

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