From: Rubén Roa-Ureta <rroa_at_udec.cl>

Date: Fri, 08 Jun 2007 11:02:09 -0400

a

b

c

matplot(p)

R-help_at_stat.math.ethz.ch mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Fri 08 Jun 2007 - 15:38:24 GMT

Date: Fri, 08 Jun 2007 11:02:09 -0400

x<-c(runif(100,10,40),runif(100,43,55)) y<-c(runif(100,7,35),runif(100,37,50)) z<-c(runif(100,10,42),runif(100,45,52)) a<-table(ceiling(x)) b<-table(ceiling(y)) c<-table(ceiling(z))

a

b

c

will give me three tables that start and end at different integer values, and besides, they have 'holes' in between different integer values. Is it possible to use 'table' to make these three tables have the same dimensions, filling in the absent labels with zeroes? In the example above, the desired tables should all start at 8 and tables 'a' and 'c' should put a zero at labels '8' to '10', should all put zeros in the frequencies of the labels corresponding to the holes, and should all end at label '55'. The final purpose is the make a matrix and use 'matplot' to plot all the frequencies in one plot, such as

#code valid only when 'a', 'b', and 'c' have the proper dimension p<-mat.or.vec(48,4)

p[,1]<-8:55 p[,2]<-c(matrix(a)[1:48]) p[,3]<-c(matrix(b)[1:48]) p[,4]<-c(matrix(c)[1:48])

matplot(p)

I read the help about 'table' but I couldn't figure out if dnn,
deparse.level, or the other arguments could serve my purpose. Thanks for
your help

Rubén

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Fri 08 Jun 2007 - 15:38:24 GMT

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