Re: [R] restructuring matrix

From: Moshe Olshansky <m_olshansky_at_yahoo.com>
Date: Wed, 27 Jun 2007 18:02:53 -0700 (PDT)


If your original matrix is A then
unique(A$People) and unique(A$Desc)
will produce a vector of different people and a vector of different descriptions.

>
> Hi all,
>
> let's say I have matrix
>
> People Desc Value
> Mary Height 50
> Mary Weight 100
> Fanny Height 60
> Fanny Height 200
>
> Is there a quick way to form the following matrix?
>
> People Height Weight
> Mary 50 100
> Fanny 60 200
>
> (Assuming I don't know the length of people/desc and
> let's say these are
> characters matrix.. I tried play with row(), col(),
> etc.. but I don't seem
> to find like a duplicate match function...
> I'm trying to write some one/two liner that convert
> my resulting matrix to
> vector and pick the appropriate fields.. etc )
>
> Thanks!
>
> --
> View this message in context:
>
http://www.nabble.com/restructuring-matrix-tf3991741.html#a11334950
> Sent from the R help mailing list archive at
> Nabble.com.
>
> ______________________________________________
> R-help_at_stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained,
> reproducible code.
>



R-help_at_stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Thu 28 Jun 2007 - 01:13:03 GMT

Archive maintained by Robert King, hosted by the discipline of statistics at the University of Newcastle, Australia.
Archive generated by hypermail 2.2.0, at Thu 28 Jun 2007 - 02:32:45 GMT.

Mailing list information is available at https://stat.ethz.ch/mailman/listinfo/r-help. Please read the posting guide before posting to the list.