From: David Winsemius <dwinsemius_at_comcast.net>

Date: Sat, 1 Dec 2007 18:40:14 +0000 (UTC)

*>
*

> My nomination for a function with a similar result would be ecdf(), the

*> empirical cumulative distribution function. It is of class "function"
*

so

> efforts to index ecdf(.)[.] failed for me.

*>
*

>> df4$V2

> [1] 1 1 1 1 1 5 6 7 9 #copied wrong line in R session

> [1] 0.2 0.2 0.4 0.4 0.5 0.6 0.7 0.8 1.0 0.9

*>
*

*> Don't have Excel, but the OpenOffice.org Calc program has the same
*

*> function. It produces:
*

*> x percentrank(x)
*

*> 1 0.0000000
*

*> 1 0.0000000
*

*> 3 0.2222222
*

*> 3 0.2222222
*

*> 4 0.4444444
*

*> 5 0.5555556
*

*> 6 0.6666667
*

*> 7 0.7777778
*

*> 10 1.0000000
*

*> 9 0.8888889
*

*>
*

*> (Not that I am saying that the OO.o/Excel function is what one _should_
*

*> want. Its behavior seems pathological to me.)
*

>

R-help_at_r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sat 01 Dec 2007 - 18:43:59 GMT

Date: Sat, 1 Dec 2007 18:40:14 +0000 (UTC)

David Winsemius <dwinsemius_at_comcast.net> wrote in news:Xns99F989B3A3057dNOTwinscomcast_at_80.91.229.13:

> "tom soyer" <tom.soyer@gmail.com> wrote in

*> news:65cc7bdf0712010951p451a993i70da89f285d801de_at_mail.gmail.com:
**>
*

>> John, >> >> The Excel's percentrank function works like this: if one has a number, >> x for example, and one wants to know the percentile of this number in >> a given data set, dataset, one would type =percentrank(dataset,x) in >> Excel to calculate the percentile. So for example, if the data set is >> c(1:10), and one wants to know the percentile of 2.5 in the data set, >> then using the percentrank function one would get 0.166, i.e., 2.5 is >> in the 16.6th percentile. >> >> I am not sure how to program this function in R. I couldn't find it as >> a built-in function in R either. It seems to be an obvious choice for >> a built-in function. I am very surprised, but maybe we both missed it.

> My nomination for a function with a similar result would be ecdf(), the

so

> efforts to index ecdf(.)[.] failed for me.

>> df4$V2

> [1] 1 1 1 1 1 5 6 7 9 #copied wrong line in R session

Make that;

df4$V2<-c(1,1,3,3,4,5,6,7,10,9)

[1] 1 1 3 3 5 6 7 9

>> ecdf.V2<-ecdf(df4$V2) >> ecdf.V2(df4$V2)

> [1] 0.2 0.2 0.4 0.4 0.5 0.6 0.7 0.8 1.0 0.9

>

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sat 01 Dec 2007 - 18:43:59 GMT

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