From: papagenic <nabble_at_dejademain.com>

Date: Wed, 23 Jan 2008 08:32:11 -0800 (PST)

}

}

Date: Wed, 23 Jan 2008 08:32:11 -0800 (PST)

I can write this in R as follows

for(i in 1:length(x)) {

y[i]=0

for(j in i:length(x)) {

if (abs(x[j]-x[i]) > step) { y[i]=sign(x[j]-x[i])*(j-i) break; }

}

}

but I wonder if there is a more efficient way to write this. I understand explicit looping can often be avoided in R using vector notation.

Thanks for your help

-- View this message in context: http://www.nabble.com/newbie%3Alooking-for-an-efficient-way-to-compute-distance-vector-tp15045583p15045583.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help_at_r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.Received on Wed 23 Jan 2008 - 16:44:26 GMT

Archive maintained by Robert King, hosted by
the discipline of
statistics at the
University of Newcastle,
Australia.

Archive generated by hypermail 2.2.0, at Wed 23 Jan 2008 - 17:30:08 GMT.

*
Mailing list information is available at https://stat.ethz.ch/mailman/listinfo/r-help.
Please read the posting
guide before posting to the list.
*