[R] How does do.call() work??

From: Sergey Goriatchev <sergeyg_at_gmail.com>
Date: Fri, 25 Jan 2008 11:27:57 +0100

Dear members of R forum,

Say I have a list:

L <- list(1:3, 1:3, 1:3)

that I want to turn into a matrix.

I wonder why if I do:

do.call(cbind, L)

I get the matrix I want, but if I do


I get something different from what I want. Why is that? How does do.call() actually work?

I've read in do.call() help file this sentence: "The behavior of some functions, such as "substitute", will not be the same for functions evaluated using do.call as if they were evaluated from the interpreter. The precise semantics are currently undefined and subject to change. "

Thanks for help!

I'm not young enough to know everything. /Oscar Wilde

Experience is one thing you can't get for nothing. /Oscar Wilde

When you are finished changing, you're finished. /Benjamin Franklin

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Received on Fri 25 Jan 2008 - 10:35:42 GMT

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