Re: [R] Dynamic string as element name in a list

From: Henrique Dallazuanna <wwwhsd_at_gmail.com>
Date: Thu, 27 Mar 2008 11:23:56 -0300

HI,

I don't understand why you're using lapply.

Please provide a example of your 'x' data.frame

str(x)

On 27/03/2008, Paul Lemmens <paul.lemmens_at_gmail.com> wrote:
> Hi Henrique,
>
>
> On Thu, Mar 27, 2008 at 2:52 PM, Henrique Dallazuanna <wwwhsd_at_gmail.com> wrote:
> > Try this:
> >

> > foo <- function(x)
> > {
> > clipname <- "LK"
> > out <- list()
> > out[[clipname]] <- rnorm(5)
> > return(out)
> > }
>
> That easy ... Hadn't thought of it. But now I have a refinement in foo()
>
> foo <- function(x) {
> out <- list()
> lapply(x$clipno, function(c) {
> clipname <- x$clipname
> # stuff
>
> out[[clipname]] <- rnorm(5)
> })
> return(out)
> }
>
>
> But this returns the/an empty list?
>
>
> Best regards,
>
> Paul Lemmens
>
> ______________________________________________
> R-help_at_r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O

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Received on Thu 27 Mar 2008 - 14:26:47 GMT

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