# Re: [R] barplot as Trellis graphic

Date: Thu, 27 Mar 2008 14:33:11 -0400

On Mar 27, 2008, at 1:47 PM, Agustin Lobo wrote:

> Thanks, it was a matter of reshaping the data matrix as I usually have
> it, ie:
> datos <-
> data.frame(x=abs(round(rnorm(100,10,5))),y=abs(round(rnorm
> (100,2,1))),f=factor(round(runif(100,1,3))))
>
> to become:
>
> datos2 <-
> data.frame(V1=c(datos[,1],datos[,2]),"VAR"=c(rep("x",100),rep("y",
> 100)),f=factor(c(datos[,3],datos[,3])))
>
> and then
> require(lattice)
> barchart(V1~VAR|f,data=datos2)
>
> I get horizontal lines in the bars that I do not understand, though.

In order to understand the lines , you should ask: What does the height of each bar correspond to? As you have set things up, the "x" bar in panel "1" should somehow correspond to the all values:

datos2\$V1[datos2\$VAR=="x" & datos2\$f==1]  15 13 14 1 18 14 8 12 7 19 10 1 5 14 7 9 14 7 5 10 6 12 10 11 11 7 15
 9 4 12 17 10 4 5

So you should ask yourself, how you expect R to produce a single column, which in some sense corresponds to just one single number, its height, from these different values. My guess is that you want R to show you just the mean on each group. For me this is not a barplot, but anyway. What happens in the barplot you have now, I think, is this that R will start by constructing a bar with height 15, then put on it a bar of height 13, then on it a bar of height 14 and so on. So the lines you see account for the boxes that survive:

> x<-datos2\$V1[datos2\$VAR=="x" & datos2\$f==1]  > unique(cummax(rev(x)))
 5 10 17 19

I would recommend using boxplots instead of "barplots only showing the means". If you really want barplots of the means, I think you can do the following:

datos3 <- with(datos2, aggregate(x=V1, by=list(VAR=VAR,f=f), mean)) barchart(x~VAR|f, datos3)

Another option would be ggplot2 I think, but I'll let someone knowledgeable with that package speak up.

> Agus
>