# Re: [R] Accessing items in a list of lists

From: Tony Plate <tplate_at_acm.org>
Date: Wed, 14 May 2008 13:49:05 -0600

Try this:

``` > data1 <- list(a = 1, b = 2, c = 3)
> data2 <- list(a = 4, b = 5, c = 6)
> data3 <- list(a = 3, b = 6, c = 9)
> comb <- list(data1 = data1, data2 = data2, data3 = data3)
> sapply(comb, "[[", "a")
data1 data2 data3
1     4     3
```

> # Also, this can be useful:
> comb[[c("data2", "b")]]
[1] 5
>

> Using R 2.6.2, say I have the following list of lists, "comb":
>
> data1 <- list(a = 1, b = 2, c = 3)
> data2 <- list(a = 4, b = 5, c = 6)
> data3 <- list(a = 3, b = 6, c = 9)
> comb <- list(data1 = data1, data2 = data2, data3 = data3)
>
> So that all names for the lowest level list are common. How can I most
> efficiently access all of the sublist items "a" indexed by the outer
> list names? For example, I can loop through comb[[i]], unlisting as I
> go, and then look up the field "a", as below, but there has got to be a
> cleaner way.
>
> finaldata <- double(0)
> for(i in 1:length(names(comb))) {
> test <- unlist(comb[[i]])
> finaldata <- c(finaldata, test[which(names(test) == "a")])
> }
> data.frame(names(comb), finaldata)
>
> Gives what I want:
> names.comb. finaldata
> 1 data1 1
> 2 data2 4
> 3 data3 3
>
> --------------------------------------------------------
>
>
>
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