# Re: [R] question for Logic Regression

From: coldeyes <coldeyes.rhelp_at_gmail.com>
Date: Mon, 19 May 2008 11:59:58 -0700 (PDT)

thanks for you response, i try predict command, it is doesn't work. i list a simulate code below:

X <- matrix(as.numeric(runif(400) < 0.5), 50,8) colnames(X) <- paste("X", 1:ncol(X), sep="") rownames(X) <- paste("case", 1:nrow(X), sep="")

# Define expected result: Y = (NOT X2) AND X6 Y <- as.numeric(!X[,2] & X[,6])

Z<-cbin(X,Y)

set.seed(12345)

Annealing <- logreg.anneal.control(start = 4, end = -4, iter = 1000, update = 50)

logicfit <- logreg(resp=Z[,9], bin=Z[,1:8],

```                   type = 3,
select = 2,
ntrees=2,
nleaves=3,
anneal.control=Annealing)

```

new<-data.frame(Z)
new<-NULL
alltrees <- predict(logicfit, new)

names(logicfit)

doesn't have coef class.

thanks

Yasir Kaheil wrote:

```>
> try
> alltrees <- predict(fit, model.dat2) # make sure response variable is not
> included in model.dat2
>
> also to see the other attributes in "fit", try: attributes(fit)
>
> thanks
> y
>
>
>
> coldeyes.Rhelp wrote:
```

>>
>> Hi All:
>>
>> how to get the coefficient for logic regression using selection=2 ( fit
>> multiple models) and type=3 ( logistic regression)
>> for example i have a fit like below :
>> fit<-logreg(resp = model.dat[,21], bin=model.dat[,
>> 2:18],sep=model.dat[,1] ,type=3,select=2,ntrees=2,nleaves=6
>> ,anneal.control=Annealing,tree.control=TreeControl)
>>
>> i try to use fit\$coef but i get nothing.
>>
>> and i try to use eval.logreg to evaluate a validate data "model.dat2",
>> but i cannot fit "model" class make below formula work
>> alltrees <- eval.logreg(fit\$model , model.dat2)
>>
>> could anyone enlighten me a little.
>> thanks
>> leo
>>
>> ______________________________________________
>> R-help_at_r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
>
```--
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