Re: [R] inverse cumsum

From: Ted Harding <Ted.Harding_at_manchester.ac.uk>
Date: Wed, 18 Jun 2008 11:50:43 +0100 (BST)


On 18-Jun-08 10:17:09, Alfredo Alessandrini wrote:
> I've a matrix like this:
>
> 1985 1.38 1.27 1.84 2.10 0.59 3.47
> 1986 1.05 1.13 1.21 1.54 0.21 2.14
> 1987 1.33 1.21 1.77 1.44 0.27 2.85
> 1988 1.86 1.06 2.33 2.14 0.55 1.40
> 1989 2.10 0.65 2.74 2.43 1.19 1.45
> 1990 1.55 0.00 1.59 1.94 0.99 2.14
> 1991 0.92 0.72 0.50 1.29 0.54 1.22
> 1992 2.15 1.28 1.23 2.26 1.22 3.17
> 1993 1.50 0.87 1.68 1.97 0.83 2.55
> 1994 0.69 0.00 0.76 1.89 0.60 0.87
> 1995 1.13 1.04 1.19 1.52 1.13 1.78
>
> Can I utilise a cumsum inverse? from 1995 to 1985?
>
> Thank you,
> Alfredo

Try on the lines of:

  cumsum(c(1,2,3,4,5))
# [1] 1 3 6 10 15
  cumsum(rev(c(1,2,3,4,5)))
# [1] 5 9 12 14 15

Hoping this helps,
Ted.



E-Mail: (Ted Harding) <Ted.Harding_at_manchester.ac.uk> Fax-to-email: +44 (0)870 094 0861
Date: 18-Jun-08                                       Time: 11:50:40
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