Re: [R] Problems with lm()

From: Dr. Christoph Scherber <Christoph.Scherber_at_agr.uni-goettingen.de>
Date: Sat, 21 Jun 2008 09:12:23 +0200 (CEST)

Dear Hsin-Ya,

Then it might be that you have checked "Type 3 sums of squares" in SPSS, while R uses type 1 by default.

>
> Dear Dr. Andrew Robinson:
>
> Thanks for your reply. In my data, subject is nested within sequence.
> According to Dr. Christoph's reply, I have change the sequence data.
> It seems not work in R. However, I am sure that I run the same data with
> GLM in SPSS that I posted in first time. I really do not know where the
> problem is. How can I do?
>
> Best regards,
> Hsin-Ya
>
>
>
>
>
> Andrew Robinson-6 wrote:
>>
>> In your data, subject is nested within sequence. Was that your
>> intention?
>>
>>> a<-c(1,1,2,2,3,3,4,4,5,5,6,6,7,7,8,8,9,9,10,10,11,11,12,12,13,13,14,14)
>>> b<-c(1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2)
>>> c<-c(2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2)
>>> d<-c(2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1)
>>> e<-c(1739,1633,1481,1837,1780,2073,1374,1629,1555,1385,1756,1522,1566,1643,
>> + 1939,1615,1475,1759,1388,1483,1127,1682,1542,1247,1235,1605,1598,1718
>> + )
>>> Data<-data.frame(subject=as.factor(a),
>> + drug=as.factor(b), period=as.factor(c),
>> + sequence=as.factor(d), Max=e)
>>> Data
>> subject drug period sequence Max
>> 1 1 1 2 2 1739
>> 2 1 2 1 2 1633
>> 3 2 1 1 1 1481
>> 4 2 2 2 1 1837
>> 5 3 1 2 2 1780
>> 6 3 2 1 2 2073
>> 7 4 1 1 1 1374
>> 8 4 2 2 1 1629
>> 9 5 1 2 2 1555
>> 10 5 2 1 2 1385
>> 11 6 1 1 1 1756
>> 12 6 2 2 1 1522
>> 13 7 1 2 2 1566
>> 14 7 2 1 2 1643
>> 15 8 1 1 1 1939
>> 16 8 2 2 1 1615
>> 17 9 1 2 2 1475
>> 18 9 2 1 2 1759
>> 19 10 1 1 1 1388
>> 20 10 2 2 1 1483
>> 21 11 1 2 2 1127
>> 22 11 2 1 2 1682
>> 23 12 1 1 1 1542
>> 24 12 2 2 1 1247
>> 25 13 1 2 2 1235
>> 26 13 2 1 2 1605
>> 27 14 1 1 1 1598
>> 28 14 2 2 1 1718
>>
>>
>>
>> Andrew
>>
>>
>> On Thu, Jun 19, 2008 at 04:29:16PM +0800, leeznar wrote:
>>> Dear R-users:
>>>
>>> I am a new R-user and I have a question about lm
>>> function. Here is my data.
>>> a<-c(1,1,2,2,3,3,4,4,5,5,6,6,7,7,8,8,9,9,10,10,11,11,12,12,13,13,14,14)
>>> b<-c(1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2,1,2)
>>> c<-c(2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2)
>>> d<-c(2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1,2,2,1,1)
>>> e<-c(1739,1633,1481,1837,1780,2073,1374,1629,1555,1385,1756,1522,1566,1643,1939,1615,1475,1759,1388,1483,1127,1682,1542,1247,1235,1605,1598,1718
>>> )
>>> Data<-data.frame(subject=as.factor(a),
>>> drug=as.factor(b), period=as.factor(c),
>>> sequence=as.factor(d), Max=e)
>>>
>>> lm3<- lm(Max ~subject*sequence + sequence + period +
>>> drug, data=Data)
>>> print(lm3)
>>> anova(lm3)
>>>
>>> When I use lm to fit the data, there are some problems
>>> in ??subject*sequence??. I have use GLM in SPSS to
>>> fit the same data, and it seems there is no problem.
>>>
>>> I don??t know where my problem is. How can I get the
>>> same result with SPSS? How can I do?
>>>
>>> Best regards,
>>> Hsin-Ya Lee
>>>
>>>
>>>
>>>
>>>
>>> ______________________________________________________________________________________________________
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>>
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>>
>>
>> --
>> Andrew Robinson
>> Department of Mathematics and Statistics Tel: +61-3-8344-6410
>> University of Melbourne, VIC 3010 Australia Fax: +61-3-8344-4599
>> http://www.ms.unimelb.edu.au/~andrewpr
>> http://blogs.mbs.edu/fishing-in-the-bay/
>>
>> ______________________________________________
>> R-help_at_r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
>
> --
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>
> ______________________________________________
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>



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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Sat 21 Jun 2008 - 07:15:07 GMT

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