Re: [R] Pairwise Partitioning of a Vector

From: Peter Dalgaard <p.dalgaard_at_biostat.ku.dk>
Date: Mon, 23 Jun 2008 08:40:10 +0200

Gundala Viswanath wrote:
> Hi,
>
> How can I partitioned an example vector like this
>
>
>> print(myvector)
>>
> [1] 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9
>
> into the following pairwise partition:
>
> PAIR1
> part1 = 30.9
> part2 = 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9
>
> PAIR2
> part1 = 30.9 60.1
> part2 = 70.0 73.0 75.0 83.9 93.1 97.6 98.8 113.9
>
> ....
>
> PAIR9
> part1 = 30.9 60.1 70.0 73.0 75.0 83.9 93.1 97.6 98.8
> part2 = 113.9
>
>
> I'm stuck with this kind of loop:
>
Your code seems strangely out of sync with your example. Why does gexp want to me a matrix and what is the sorting for??

How about

lapply(1:9, function(n) {ix <- seq_len(n); list(part1=myvector[ix], part2=myvector[-ix])})

?

> __BEGIN__
>
> # gexp is a Vector
>
> process_two_partition <- function(gexp) {
> sort.gexp <- sort(as.matrix(gexp))
> print(sort.gexp)
>
> for (posb in 1:ncol(gexp)) {
> for (pose in 1:ncol(gexp)) {
>
> sp_b <- pose+1
> sp_e <- ncol(gexp)
>
> # This two doesn't do what I want
> part1 <- sort.gexp[posb:pose]
> part2 <- sort.gexp[sp_b:sp_e]
>
> # we later want to process part1 and part2 separately
>
> }
> }
>
> }
>
> __END__
>
> - Gundala Viswanath
> Jakarta - Indonesia
>
> ______________________________________________
> R-help_at_r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

-- 
   O__  ---- Peter Dalgaard             ุster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics     PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark      Ph:  (+45) 35327918
~~~~~~~~~~ - (p.dalgaard_at_biostat.ku.dk)              FAX: (+45) 35327907

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Received on Mon 23 Jun 2008 - 06:44:52 GMT

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