Re: [R] NA value

From: Jorge Ivan Velez <jorgeivanvelez_at_gmail.com>
Date: Fri, 27 Jun 2008 11:41:56 -0400

Dear K. Elo,

You're right!

cimfasy_rwl=read.table(textConnection("1991     0.92     0.72     0.50
1.29     0.54     1.22
1992     2.15     1.28     1.23     2.26     1.22     3.17
1993     1.50     0.87     1.68     1.97     0.83     2.55
1994     0.69     0.00     0.76     1.89     0.60     0.87
1995     1.13     1.04     1.19     1.52     1.13     1.78
1996     1.15     0.92     1.50     0.97     0.60       NA
1997       NA       NA       NA       NA       NA       NA
1998       NA       NA       NA       NA       NA       NA
1999       NA       NA       NA       NA       NA       NA
2000       NA       NA       NA       NA       NA
NA"),sep="",header=FALSE)

cimfasy_rwl[is.na(cimfasy_rwl)]<-0
cimfasy_rwl
 V1 V2 V3 V4 V5 V6 V7

1  1991 0.92 0.72 0.50 1.29 0.54 1.22
2  1992 2.15 1.28 1.23 2.26 1.22 3.17
3  1993 1.50 0.87 1.68 1.97 0.83 2.55
4  1994 0.69 0.00 0.76 1.89 0.60 0.87
5  1995 1.13 1.04 1.19 1.52 1.13 1.78
6  1996 1.15 0.92 1.50 0.97 0.60 0.00
7  1997 0.00 0.00 0.00 0.00 0.00 0.00
8  1998 0.00 0.00 0.00 0.00 0.00 0.00
9  1999 0.00 0.00 0.00 0.00 0.00 0.00
10 2000 0.00 0.00 0.00 0.00 0.00 0.00

HTH, Jorge

On Fri, Jun 27, 2008 at 11:13 AM, K. Elo <maillists_at_nic.fi> wrote:

> Hi,
>
> cimfasy_rwl[ is.na(cimfasy_rwl) ] <-0
>
> Or did I understood Your right?
>
> HTH,
> Kimmo
>
>
>
> Alfredo Alessandrini wrote:
>
>> I'm trying to replace NA with 0 value...
>>
>> I've write a loop, but don't work...
>>
>> Where's the problem?
>>
>>
>> cimfasy_rwl
>>>
>> 1991 0.92 0.72 0.50 1.29 0.54 1.22
>> 1992 2.15 1.28 1.23 2.26 1.22 3.17
>> 1993 1.50 0.87 1.68 1.97 0.83 2.55
>> 1994 0.69 0.00 0.76 1.89 0.60 0.87
>> 1995 1.13 1.04 1.19 1.52 1.13 1.78
>> 1996 1.15 0.92 1.50 0.97 0.60 NA
>> 1997 NA NA NA NA NA NA
>> 1998 NA NA NA NA NA NA
>> 1999 NA NA NA NA NA NA
>> 2000 NA NA NA NA NA NA
>>
>>> files_rwl <- ls(pattern="_rwl$")
>>> files_rwl
>>>
>> [1] "cimfasy_rwl" "rocquce_rwl"
>>
>>> for (i in files_rwl) assign(i,i[is.na(i)] <- 0)
>>> ls()
>>>
>> [1] "cimfasy_rwl" "files_rwl" "files.rwl" "i" "rocquce_rwl"
>>
>>> cimfasy_rwl
>>>
>> [1] 0
>>
>>
>> Thanks in advance,
>>
>> Alfredo
>>
>> ______________________________________________
>> R-help_at_r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
> ______________________________________________
> R-help_at_r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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