From: Daniel Malter <daniel_at_umd.edu>

Date: Wed, 09 Jul 2008 06:10:23 -0400

for(i in 0:your.favorite.n){

cuncta stricte discussurus

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.

R-help_at_r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 09 Jul 2008 - 10:15:24 GMT

Date: Wed, 09 Jul 2008 06:10:23 -0400

your.number=15000 your.denominator=5 your.favorite.n=9 your.vector=NULL

for(i in 0:your.favorite.n){

your.vector[i+1]=your.number/your.denominator^i
your.vector[your.favorite.n+1]=0

}

your.vector ##check

Best,

Daniel

cuncta stricte discussurus

-----Ursprüngliche Nachricht-----

Von: r-help-bounces_at_r-project.org [mailto:r-help-bounces_at_r-project.org] Im
Auftrag von Anne-Marie Ternes

Gesendet: Wednesday, July 09, 2008 5:40 AM
An: r-help_at_r-project.org

Betreff: [R] recursively divide a value to get a sequence

Hi,

if given the value of, say, 15000, I would like to be able to divide that value recursively by, say, 5, and to get a vector of a determined length, say 9, the last value being (set to) zero- i.e. like this:

15000 3000 600 120 24 4.8 0.96 0.192 0

I suppose I could do something "loopy", but I'm sure there is a better way to do it.

Thanks a lot for your help, hope the question is not too dumb...

Anne-Marie

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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.

R-help_at_r-project.org mailing list

https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Wed 09 Jul 2008 - 10:15:24 GMT

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