# Re: [R] shifting data in matrix by n rows

Date: Thu, 10 Jul 2008 15:24:52 -0700 (PDT)

This is great! Thank you very much Gabor. rcoder

Gabor Grothendieck wrote:
>
> See ?lag and in zoo ?lag.zoo. Both pages have
> examples. Using lag.zoo here it is with your data:
>
> Lines <- "Date Apples Oranges Pears
> 1/7 2 3 5
> 2/7 1 4 7
> 3/7 3 8 10
> 4/7 5 7 2
> 5/7 6 3 5"
>
> library(zoo)
>
>
> lag(z, -1, na.pad = TRUE)
>
> On Thu, Jul 10, 2008 at 3:12 PM, rcoder <michael.larsson_at_gmail.com> wrote:

>>
>> Hi everyone,
>>
>> Thanks very much for all your replies.
>>
>> I'm interested in hearing more about the lag function. I remember coming
>> across this in the R intro manual, but I couldn't figure out how to apply
>> it
>> to my case. Does anyone know how it is applied, assuming a time series
>> data
>> frame?
>>
>> Thanks,
>>
>> rcoder
>>
>>
>>
>> Gabor Grothendieck wrote:
>>>
>>> If its a zoo or ts time series you can use the lag function.
>>>
>>> On Wed, Jul 9, 2008 at 2:57 PM, rcoder <michael.larsson_at_gmail.com>
>>> wrote:
>>>>
>>>> Hi everyone,
>>>>
>>>> I have some data in a matrix, and I want to shift it down by one row.
>>>> The
>>>> matrix in question has a date column. Does anyone know of a way to
>>>> shift
>>>> the
>>>> data by one row, whilst preserving the date column in the matrix - i.e.
>>>> shift the data and leave the date column in the current location?
>>>>
>>>> Thanks,
>>>>
>>>> rcoder
>>>> --
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>>>>
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>>>>
>>>
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>>
>> --
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>>
>> ______________________________________________
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>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
--
View this message in context: http://www.nabble.com/shifting-data-in-matrix-by-n-rows-tp18368420p18393177.html
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