Re: [R] rm(l*)

From: Gabor Csardi <csardi_at_rmki.kfki.hu>
Date: Mon, 14 Jul 2008 03:51:50 -0500

Maybe there is a simpler way, but this works fine:

> l1 <- 1
> l2 <-2
> m <-10
> ls()

[1] "l1" "l2" "m"
> rm(list=grep("^l.*", ls(), value=TRUE))
> ls()


[1] "m"
>

You can supply a regular expression to grep.

Gabor

On Mon, Jul 14, 2008 at 10:45:13AM +0200, Oehler, Friderike (AGPP) wrote:
> Dear Rusers,
>
> how can I designate various objects the names of which start (or end) with
> the same letter to remove them all together?
>
> For instance:
> > ls()
> "a","b","c","l1","l2","x"
> > rm(list=ls("l*"))
> > ls()
> "a","b","c",""x"
>
> Is there some parallel to the MySQL query: where col1 like "l%"
>
> Thanks a lot in advance,
> Friderike
>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
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-- 
Csardi Gabor <csardi_at_rmki.kfki.hu>    UNIL DGM

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Received on Mon 14 Jul 2008 - 09:04:56 GMT

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