Re: [R] finding a faster way to do an iterative computation

From: Christos Hatzis <christos.hatzis_at_nuverabio.com>
Date: Tue, 29 Jul 2008 16:55:08 -0400

matrix(rep(x, each=13) - xk, nrow=13)

> -----Original Message-----
> From: r-help-bounces_at_r-project.org
> [mailto:r-help-bounces_at_r-project.org] On Behalf Of dxc13
> Sent: Tuesday, July 29, 2008 2:13 PM
> To: r-help_at_r-project.org
> Subject: [R] finding a faster way to do an iterative computation
>
>
> useR's,
>
> I am trying trying to find out if there is a faster way to do
> a certain computation. I have successfully used FOR loops
> and the apply function to do this, but it can take some time
> to fully compute, but I was wondering if anyone may know of a
> different function or way to do this:
> > x
> [1] 1 2 3 4 5
> > xk
> [1] 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0
>
> I want to do: abs(x-xk[i]) where i = 1 to length(xk)=13. It
> should result in a 13 by 5 matrix or data frame. Does anyone
> have a "quicker" solution than FOR loops or apply()?
>
> Much appreciation and thanks,
> dxc13
> --
> View this message in context:
> http://www.nabble.com/finding-a-faster-way-to-do-an-iterative-
> computation-tp18718233p18718233.html
> Sent from the R help mailing list archive at Nabble.com.
>
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>



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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Received on Tue 29 Jul 2008 - 20:54:08 GMT

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