Re: [R] Tagging identical rows of a matrix

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From: Gabor Grothendieck (ggrothendieck@myway.com)
Date: Sat 15 May 2004 - 05:47:56 EST


Message-id: <loom.20040514T210853-410@post.gmane.org>


The shortest expression I can think of is:

as.numeric(interaction(mat[,1],mat[,2],drop=T))

Completing the thought of those who suggested dist or
unique:

N <- nrow(mat)
dd <- as.matrix(dist(rbind(mat,unique(mat))))[-seq(N),seq(N)]
apply(dd,2,function(x)match(0,x))

Scott Waichler <scott.waichler <at> pnl.gov> writes:

:
: I would like to generate a vector having the same length
: as the number of rows in a matrix. The vector should contain
: an integer indicating the "group" of the row, where identical
: matrix rows are in a group, and a unique row has a unique integer.
: Thus, for
:
: a <- c(1,2)
: b <- c(1,3)
: c <- c(1,2)
: d <- c(1,2)
: e <- c(1,3)
: f <- c(2,1)
: mat <- rbind(a,b,c,d,e,f)
:
: I would like to get the vector c(1,2,1,1,2,3). I know dist() gives
: part of the answer, but I can't figure out how to use it for
: this purpose without doing a lot of looping. I need to apply this
: to matrices up to ~100000 rows.
:
: Thanks,
: Scott Waichler
: Pacific Northwest National Laboratory
: scott.waichler_at_pnl.gov

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