RE: [R] SCO & R

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From: Thomas Lumley (tlumley@u.washington.edu)
Date: Fri 28 May 2004 - 06:11:56 EST


Message-id: <Pine.A41.4.58.0405271308150.89532@homer05.u.washington.edu>

On Thu, 27 May 2004, Mark Fowle wrote:

> I'm a bit over my head hear, but my understanding is that R is a derivative
> of S and is fully endorsed by the S group(I can not find any references at
> the moment, but I believe that there is information on this somewhere with
> in the R web site).

No, this is not at all the case. R is not a derivative of S, it is an
independent implementation of the published descriptions of S (with some
differences).

        -thomas

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