Re: [R] Question on statistics

From: Kjetil Brinchmann Halvorsen <kjetil_at_acelerate.com>
Date: Thu 24 Mar 2005 - 03:51:25 EST

Roy Werkman wrote:

>Yes, it is discrete, but the underlying distribution is Gaussian.
>
>
/ I guess you mean what somebody calls the superpopulation distribution.

Kjetil
/

>Just got the following from a college:
>
>Var(mean of finite population) = ((N - n)/(N - 1)) * var(population) / n
>
>This should be it...
>
>Greetings,
>Roy
>
>-----Original Message-----
>From: Liaw, Andy [mailto:andy_liaw@merck.com]
>Sent: Wednesday, March 23, 2005 2:17 PM
>To: Roy Werkman; r-help@stat.math.ethz.ch
>Subject: RE: [R] Question on statistics
>
>If the sample is drawn with replacement from the finite population, then
>the usual formula applies (assuming iid samples); i.e., var(sample mean)
>=
>var(population) / n.
>
>There's some problem in your description: A finite population, I
>believe, is necessarily discrete (since there are only N possible
>values), so it can not be Gaussian (i.e., normal).
>
>Andy
>
>
>
>>From: Roy Werkman
>>
>>Ehh, by limited distribution, I meant to say a population of N points.
>>
>>...
>>
>>Hi,
>>
>>Can anyone help me with the following (although not directly
>>correlated to R functionality)? I have been looking on the internet
>>but can not find the answer.
>>
>>My question: what is the variation on the mean of a limited
>>distribution (total N points normally distributed), when I have a
>>small sample of that distribution (n < N)?
>>
>>Your help would be very welcome.
>>
>>Thanx,
>>Roy
>>
>>
>>--
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>>
>
>
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-- 

Kjetil Halvorsen.

Peace is the most effective weapon of mass construction.
               --  Mahdi Elmandjra





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Received on Thu Mar 24 04:22:38 2005

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