RE: [R] Stats Question: Single data item versus Sample from Norma l Distribution

From: Liaw, Andy <andy_liaw_at_merck.com>
Date: Tue 05 Apr 2005 - 20:38:35 EST


> From: Liaw, Andy
>
> Here's one possibility, assuming muhat and sigmahat are
> estimtes of mu and sigma from N iid draws of N(mu, sigma^2):
>
> tStat <- abs(x - muhat) / sigmahat
> pValue <- pt(tStat, df=N, lower=TRUE)

Oops... That should be:

pValue <- pt(tStat, df=N, lower=TRUE) / 2

Andy

>
> I'm not quite sure what df tStat should have (exercise for
> math stat), but given fairly large N, that should make little
> difference.
>
> Andy
>
> > From: Ross Clement
> >
> > Hi. I have a question that I have asked in other stat forums
> > but do not
> > yet have an answer for. I would like to know if there is
> some way in R
> > or otherwise of performing the following hypothesis test.
> >
> > I have a single data item x. The null hypothesis is that x
> > was selected
> > from a normal distribution N(mu,sigma). The alternate
> > hypothesis is that
> > x does not come from this distribution.
> >
> > However, I do not know the values of mu and sigma. I have a
> sample of
> > size N from which I can estimate mu and sigma. So, say that I have
> > N(m,s,N), and x. I would like to say with some certainty
> > (e.g. 95%) that
> > I can, or can't reject the hypothesis that x came from
> N(mu,sigma). I
> > would also like a power test to say how large N should be given the
> > degree of accuracy I need when accepting or rejecting individual x
> > values.
> >
> > What is the name of the hypothesis test I need for this? Is it built
> > into R, or are there packages I could use?
> >
> > Thanks in anticipation,
> >
> > Ross Clement.
> >
> > ______________________________________________
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> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide!
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> >
> >
> >
>



R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Tue Apr 05 20:45:45 2005

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