[R] Inf +1i vs 1+Inf*1i

From: Robin Hankin <r.hankin_at_soc.soton.ac.uk>
Date: Wed 13 Apr 2005 - 17:51:19 EST


Hi

If I have

a <- Inf + 1i

then

Re(a) is Inf, and Im(a) is 1, as expected.

But if

b <- 1 + Inf * 1i,

then

Im(b) = Inf , as expected, but Re(b) = NaN, which I didn't expect.

Why this asymmetry? How to define an object with Re(b)=1, Im(b)=Inf?

--
Robin Hankin
Uncertainty Analyst
Southampton Oceanography Centre
European Way, Southampton SO14 3ZH, UK
  tel  023-8059-7743

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Received on Wed Apr 13 17:56:28 2005

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