Re: [R] simplify loop

From: Prof Brian Ripley <ripley_at_stats.ox.ac.uk>
Date: Thu 12 May 2005 - 03:32:38 EST

It is, backwards, a cumulative product so you could use cumprod.

On Wed, 11 May 2005, Omar Lakkis wrote:

> Is there a way to implement this faster than doing it in a loop.
>
> for (i in length(settle)-1:1) {
> settle[i] = settle[i+1]/(1 + settle.pct[i+1])
> }
>
> I want to guarantee that i+1 is calculated before i
>
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-- 
Brian D. Ripley,                  ripley@stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
1 South Parks Road,                     +44 1865 272866 (PA)
Oxford OX1 3TG, UK                Fax:  +44 1865 272595

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Received on Thu May 12 03:38:30 2005

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