From: Weiwei Shi <helprhelp_at_gmail.com>

Date: Sat 04 Jun 2005 - 05:07:57 EST

Date: Sat 04 Jun 2005 - 05:07:57 EST

Hi,

I have one question on factor vector.

I have 3 factor vectors:

a<-factor(c("1", "2", "3")) b<-factor(c("a", "b", "c")) c<-factor(c("b", "a", "c"))

what I want is like:

c x

1 b 2

2 a 1

3 c 3

which means, I use b as keys and vector a as values and I find values for c.

I used the following codes:

x<-c()

d<-data.frame(b,a)

for (each in 1:length(c)){ # i don't know why each in c did not work

tmp<-d$a[d$b==c[each]] # questionx<-append(x, levels(tmp)[as.integer(tmp)]) }

data.frame(c,x)

If someone has a better way to do it, please help!!

Also, I don't understand why I have to use levels() since w/o it, i only added the index for levels in to x.

BTW, when b is like 60,000, the process is very slow. Should I use hash here?

Thanks,

Weiwei

-- Weiwei Shi, Ph.DReceived on Sat Jun 04 05:16:32 2005

"Did you always know?"

"No, I did not. But I believed..."

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