[R] calculate likelihood based on logit regression

From: Haibo Huang <edhuang00_at_yahoo.com>
Date: Sat 06 Aug 2005 - 03:05:22 EST


I just ran the following logit regression. But can anyone tell me how to calculate how much more likely males (Male=1) could show such symptom than females(Male=0)? I know it must be simple to get once I have the coefficients, but I just don't recall. Thank you very much!

glm(formula = Symptoms ~ 1 + Male, family = binomial(link = logit),

    data = HA)
Deviance Residuals:

       Min 1Q Median 3Q Max
-6.038e+03 -2.067e-06 0.000e+00 0.000e+00 6.720e+03

                      Estimate Std. Error    z value
(Intercept)          5.711e+00  8.466e-02  6.746e+01  
<2e-16 ***
Male        -6.493e+00  8.540e-02 -7.603e+01   <2e-16


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https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html Received on Sat Aug 06 03:15:51 2005

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